-28+r=6(1+6r)+1

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Solution for -28+r=6(1+6r)+1 equation: 



-28+r=6(1+6r)+1

We move all terms to the left:

-28+r-(6(1+6r)+1)=0

We add all the numbers together, and all the variables

r-(6(6r+1)+1)-28=0



We calculate terms in parentheses: -(6(6r+1)+1), so:

6(6r+1)+1

We multiply parentheses

36r+6+1

We add all the numbers together, and all the variables

36r+7

Back to the equation:

-(36r+7)



We get rid of parentheses

r-36r-7-28=0

We add all the numbers together, and all the variables

-35r-35=0

We move all terms containing r to the left, all other terms to the right

-35r=35

r=35/-35

r=-1

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