-28-(8x+28)=64+4x

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Solution for -28-(8x+28)=64+4x equation: 



-28-(8x+28)=64+4x

We move all terms to the left:

-28-(8x+28)-(64+4x)=0

We add all the numbers together, and all the variables

-(8x+28)-(4x+64)-28=0

We get rid of parentheses

-8x-4x-28-64-28=0

We add all the numbers together, and all the variables

-12x-120=0

We move all terms containing x to the left, all other terms to the right

-12x=120

x=120/-12

x=-10

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