-28=-4(1+3x)-6(x-2)

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Solution for -28=-4(1+3x)-6(x-2) equation: 



-28=-4(1+3x)-6(x-2)

We move all terms to the left:

-28-(-4(1+3x)-6(x-2))=0

We add all the numbers together, and all the variables

-(-4(3x+1)-6(x-2))-28=0



We calculate terms in parentheses: -(-4(3x+1)-6(x-2)), so:

-4(3x+1)-6(x-2)

We multiply parentheses

-12x-6x-4+12

We add all the numbers together, and all the variables

-18x+8

Back to the equation:

-(-18x+8)



We get rid of parentheses

18x-8-28=0

We add all the numbers together, and all the variables

18x-36=0

We move all terms containing x to the left, all other terms to the right

18x=36

x=36/18

x=2

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