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3;8;3;10;1;3
(2*x^2+1)/(x^3-1)
3;8;3;10;1;3
3*abs(x) = 0;x
x
(x^2+3)/(2*x-1)
| 24p+32+1=36p-1 | | 3x-14y= | | -(1+7v)-6(-7-x)=36 | | -529=6b+-67 | | 17-x=-69 | | 19-y=9 | | 22x-7=6x+41 | | 3[5-(y+3)]= | | 8y-3=5y+30 | | 28(q-947)=812 | | x-4/5=81/3 | | 79+22+x=180 | | 16(j-991)=-400 | | 79+22+6=180 | | 106-7t=50 | | -7*3sqrt(11*2-4)=-42 | | 3n-15=39 | | 48=3(v-63) | | 2h+(8h-3)=0 | | 167+4w=863 | | 2n-7=53 | | -7*3sqrt(11x-4)=-42 | | 4b-6=2b+11 | | 3d-12=48 | | 45x+5=185 | | x^2+3x-24=4x-4 | | 10x-190=2x+50 | | 10x-190=2x+53 | | x^2-5x-4=-4x+2 | | 12a^2+36=0 | | 10=c/31 | | 10x-190=2x+55 |