-28=-8y+4(y+3)

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Solution for -28=-8y+4(y+3) equation: 



-28=-8y+4(y+3)

We move all terms to the left:

-28-(-8y+4(y+3))=0



We calculate terms in parentheses: -(-8y+4(y+3)), so:

-8y+4(y+3)

We multiply parentheses

-8y+4y+12

We add all the numbers together, and all the variables

-4y+12

Back to the equation:

-(-4y+12)



We get rid of parentheses

4y-12-28=0

We add all the numbers together, and all the variables

4y-40=0

We move all terms containing y to the left, all other terms to the right

4y=40

y=40/4

y=10

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