-28=-8y+6(y-2)

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Solution for -28=-8y+6(y-2) equation: 



-28=-8y+6(y-2)

We move all terms to the left:

-28-(-8y+6(y-2))=0



We calculate terms in parentheses: -(-8y+6(y-2)), so:

-8y+6(y-2)

We multiply parentheses

-8y+6y-12

We add all the numbers together, and all the variables

-2y-12

Back to the equation:

-(-2y-12)



We get rid of parentheses

2y+12-28=0

We add all the numbers together, and all the variables

2y-16=0

We move all terms containing y to the left, all other terms to the right

2y=16

y=16/2

y=8

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