-28=2(-8k-1)-3(k-4)

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Solution for -28=2(-8k-1)-3(k-4) equation: 



-28=2(-8k-1)-3(k-4)

We move all terms to the left:

-28-(2(-8k-1)-3(k-4))=0



We calculate terms in parentheses: -(2(-8k-1)-3(k-4)), so:

2(-8k-1)-3(k-4)

We multiply parentheses

-16k-3k-2+12

We add all the numbers together, and all the variables

-19k+10

Back to the equation:

-(-19k+10)



We get rid of parentheses

19k-10-28=0

We add all the numbers together, and all the variables

19k-38=0

We move all terms containing k to the left, all other terms to the right

19k=38

k=38/19

k=2

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