-28=2(v-2)-8v

Solution for -28=2(v-2)-8v equation:

-28=2(v-2)-8v

We move all terms to the left:

-28-(2(v-2)-8v)=0


We calculate terms in parentheses: -(2(v-2)-8v), so:

2(v-2)-8v

We add all the numbers together, and all the variables

-8v+2(v-2)

We multiply parentheses

-8v+2v-4

We add all the numbers together, and all the variables

-6v-4

Back to the equation:

-(-6v-4)


We get rid of parentheses

6v+4-28=0

We add all the numbers together, and all the variables

6v-24=0

We move all terms containing v to the left, all other terms to the right

6v=24

v=24/6

v=4