-28=4(2n+2)-2(8n-2)

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Solution for -28=4(2n+2)-2(8n-2) equation: 



-28=4(2n+2)-2(8n-2)

We move all terms to the left:

-28-(4(2n+2)-2(8n-2))=0



We calculate terms in parentheses: -(4(2n+2)-2(8n-2)), so:

4(2n+2)-2(8n-2)

We multiply parentheses

8n-16n+8+4

We add all the numbers together, and all the variables

-8n+12

Back to the equation:

-(-8n+12)



We get rid of parentheses

8n-12-28=0

We add all the numbers together, and all the variables

8n-40=0

We move all terms containing n to the left, all other terms to the right

8n=40

n=40/8

n=5

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