-28=5(u-4)+3u

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Solution for -28=5(u-4)+3u equation: 



-28=5(u-4)+3u

We move all terms to the left:

-28-(5(u-4)+3u)=0



We calculate terms in parentheses: -(5(u-4)+3u), so:

5(u-4)+3u

We add all the numbers together, and all the variables

3u+5(u-4)

We multiply parentheses

3u+5u-20

We add all the numbers together, and all the variables

8u-20

Back to the equation:

-(8u-20)



We get rid of parentheses

-8u+20-28=0

We add all the numbers together, and all the variables

-8u-8=0

We move all terms containing u to the left, all other terms to the right

-8u=8

u=8/-8

u=-1

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