-28=6(v-2)-8v

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Solution for -28=6(v-2)-8v equation:



-28=6(v-2)-8v
We move all terms to the left:
-28-(6(v-2)-8v)=0
We calculate terms in parentheses: -(6(v-2)-8v), so:
6(v-2)-8v
We add all the numbers together, and all the variables
-8v+6(v-2)
We multiply parentheses
-8v+6v-12
We add all the numbers together, and all the variables
-2v-12
Back to the equation:
-(-2v-12)
We get rid of parentheses
2v+12-28=0
We add all the numbers together, and all the variables
2v-16=0
We move all terms containing v to the left, all other terms to the right
2v=16
v=16/2
v=8

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