-28=6(y-3)-8y

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Solution for -28=6(y-3)-8y equation: 



-28=6(y-3)-8y

We move all terms to the left:

-28-(6(y-3)-8y)=0



We calculate terms in parentheses: -(6(y-3)-8y), so:

6(y-3)-8y

We add all the numbers together, and all the variables

-8y+6(y-3)

We multiply parentheses

-8y+6y-18

We add all the numbers together, and all the variables

-2y-18

Back to the equation:

-(-2y-18)



We get rid of parentheses

2y+18-28=0

We add all the numbers together, and all the variables

2y-10=0

We move all terms containing y to the left, all other terms to the right

2y=10

y=10/2

y=5

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