-28=8(v-5)-2v

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Solution for -28=8(v-5)-2v equation: 



-28=8(v-5)-2v

We move all terms to the left:

-28-(8(v-5)-2v)=0



We calculate terms in parentheses: -(8(v-5)-2v), so:

8(v-5)-2v

We add all the numbers together, and all the variables

-2v+8(v-5)

We multiply parentheses

-2v+8v-40

We add all the numbers together, and all the variables

6v-40

Back to the equation:

-(6v-40)



We get rid of parentheses

-6v+40-28=0

We add all the numbers together, and all the variables

-6v+12=0

We move all terms containing v to the left, all other terms to the right

-6v=-12

v=-12/-6

v=+2

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