-28x+6=-3(1+7x)7x

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Solution for -28x+6=-3(1+7x)7x equation:



-28x+6=-3(1+7x)7x
We move all terms to the left:
-28x+6-(-3(1+7x)7x)=0
We add all the numbers together, and all the variables
-28x-(-3(7x+1)7x)+6=0
We calculate terms in parentheses: -(-3(7x+1)7x), so:
-3(7x+1)7x
We multiply parentheses
-147x^2-21x
Back to the equation:
-(-147x^2-21x)
We get rid of parentheses
147x^2+21x-28x+6=0
We add all the numbers together, and all the variables
147x^2-7x+6=0
a = 147; b = -7; c = +6;
Δ = b2-4ac
Δ = -72-4·147·6
Δ = -3479
Delta is less than zero, so there is no solution for the equation

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