-29+21t=7(3t-5)+6

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Solution for -29+21t=7(3t-5)+6 equation: 



-29+21t=7(3t-5)+6

We move all terms to the left:

-29+21t-(7(3t-5)+6)=0



We calculate terms in parentheses: -(7(3t-5)+6), so:

7(3t-5)+6

We multiply parentheses

21t-35+6

We add all the numbers together, and all the variables

21t-29

Back to the equation:

-(21t-29)



We get rid of parentheses

21t-21t+29-29=0

We add all the numbers together, and all the variables

=0

t=0/1

t=0

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