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-29+x=-8+3(x-5)
We move all terms to the left:
-29+x-(-8+3(x-5))=0
We calculate terms in parentheses: -(-8+3(x-5)), so:We get rid of parentheses
-8+3(x-5)
determiningTheFunctionDomain 3(x-5)-8
We multiply parentheses
3x-15-8
We add all the numbers together, and all the variables
3x-23
Back to the equation:
-(3x-23)
x-3x+23-29=0
We add all the numbers together, and all the variables
-2x-6=0
We move all terms containing x to the left, all other terms to the right
-2x=6
x=6/-2
x=-3
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