-29-2k=3(k-3)

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Solution for -29-2k=3(k-3) equation: 



-29-2k=3(k-3)

We move all terms to the left:

-29-2k-(3(k-3))=0



We calculate terms in parentheses: -(3(k-3)), so:

3(k-3)

We multiply parentheses

3k-9

Back to the equation:

-(3k-9)



We get rid of parentheses

-2k-3k+9-29=0

We add all the numbers together, and all the variables

-5k-20=0

We move all terms containing k to the left, all other terms to the right

-5k=20

k=20/-5

k=-4

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