-29=2(1+4n)+5(n-1)

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Solution for -29=2(1+4n)+5(n-1) equation: 



-29=2(1+4n)+5(n-1)

We move all terms to the left:

-29-(2(1+4n)+5(n-1))=0

We add all the numbers together, and all the variables

-(2(4n+1)+5(n-1))-29=0



We calculate terms in parentheses: -(2(4n+1)+5(n-1)), so:

2(4n+1)+5(n-1)

We multiply parentheses

8n+5n+2-5

We add all the numbers together, and all the variables

13n-3

Back to the equation:

-(13n-3)



We get rid of parentheses

-13n+3-29=0

We add all the numbers together, and all the variables

-13n-26=0

We move all terms containing n to the left, all other terms to the right

-13n=26

n=26/-13

n=-2

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