-29=2(q-3)-11

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Solution for -29=2(q-3)-11 equation: 



-29=2(q-3)-11

We move all terms to the left:

-29-(2(q-3)-11)=0



We calculate terms in parentheses: -(2(q-3)-11), so:

2(q-3)-11

We multiply parentheses

2q-6-11

We add all the numbers together, and all the variables

2q-17

Back to the equation:

-(2q-17)



We get rid of parentheses

-2q+17-29=0

We add all the numbers together, and all the variables

-2q-12=0

We move all terms containing q to the left, all other terms to the right

-2q=12

q=12/-2

q=-6

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