-29=2(y-4)-5

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Solution for -29=2(y-4)-5 equation:



-29=2(y-4)-5
We move all terms to the left:
-29-(2(y-4)-5)=0
We calculate terms in parentheses: -(2(y-4)-5), so:
2(y-4)-5
We multiply parentheses
2y-8-5
We add all the numbers together, and all the variables
2y-13
Back to the equation:
-(2y-13)
We get rid of parentheses
-2y+13-29=0
We add all the numbers together, and all the variables
-2y-16=0
We move all terms containing y to the left, all other terms to the right
-2y=16
y=16/-2
y=-8

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