-29=3+5(c+4)

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Solution for -29=3+5(c+4) equation: 



-29=3+5(c+4)

We move all terms to the left:

-29-(3+5(c+4))=0



We calculate terms in parentheses: -(3+5(c+4)), so:

3+5(c+4)

determiningTheFunctionDomain
5(c+4)+3

We multiply parentheses

5c+20+3

We add all the numbers together, and all the variables

5c+23

Back to the equation:

-(5c+23)



We get rid of parentheses

-5c-23-29=0

We add all the numbers together, and all the variables

-5c-52=0

We move all terms containing c to the left, all other terms to the right

-5c=52

c=52/-5

c=-10+2/5

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