-29p-6(2-6p)=3(p-5)-33

Solution for -29p-6(2-6p)=3(p-5)-33 equation:

-29p-6(2-6p)=3(p-5)-33

We move all terms to the left:

-29p-6(2-6p)-(3(p-5)-33)=0

We add all the numbers together, and all the variables

-29p-6(-6p+2)-(3(p-5)-33)=0

We multiply parentheses

-29p+36p-(3(p-5)-33)-12=0


We calculate terms in parentheses: -(3(p-5)-33), so:

3(p-5)-33

We multiply parentheses

3p-15-33

We add all the numbers together, and all the variables

3p-48

Back to the equation:

-(3p-48)


We add all the numbers together, and all the variables

7p-(3p-48)-12=0

We get rid of parentheses

7p-3p+48-12=0

We add all the numbers together, and all the variables

4p+36=0

We move all terms containing p to the left, all other terms to the right

4p=-36

p=-36/4

p=-9