-2=-3(2x+3)7x

Solution for -2=-3(2x+3)7x equation:

-2=-3(2x+3)7x

We move all terms to the left:

-2-(-3(2x+3)7x)=0


We calculate terms in parentheses: -(-3(2x+3)7x), so:

-3(2x+3)7x

We multiply parentheses

-42x^2-63x

Back to the equation:

-(-42x^2-63x)


We get rid of parentheses

42x^2+63x-2=0

a = 42; b = 63; c = -2;
Δ = b2-4ac
Δ = 632-4·42·(-2)
Δ = 4305
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-\sqrt{4305}}{2*42}=\frac{-63-\sqrt{4305}}{84}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+\sqrt{4305}}{2*42}=\frac{-63+\sqrt{4305}}{84}
$