-2=2/3x-x

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Solution for -2=2/3x-x equation:



-2=2/3x-x
We move all terms to the left:
-2-(2/3x-x)=0
Domain of the equation: 3x-x)!=0
x∈R
We add all the numbers together, and all the variables
-(-1x+2/3x)-2=0
We get rid of parentheses
1x-2/3x-2=0
We multiply all the terms by the denominator
1x*3x-2*3x-2=0
Wy multiply elements
3x^2-6x-2=0
a = 3; b = -6; c = -2;
Δ = b2-4ac
Δ = -62-4·3·(-2)
Δ = 60
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{60}=\sqrt{4*15}=\sqrt{4}*\sqrt{15}=2\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{15}}{2*3}=\frac{6-2\sqrt{15}}{6} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{15}}{2*3}=\frac{6+2\sqrt{15}}{6} $

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