-2=3(y-2)-y=

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Solution for -2=3(y-2)-y= equation: 



-2=3(y-2)-y=

We move all terms to the left:

-2-(3(y-2)-y)=0



We calculate terms in parentheses: -(3(y-2)-y), so:

3(y-2)-y

We add all the numbers together, and all the variables

-1y+3(y-2)

We multiply parentheses

-1y+3y-6

We add all the numbers together, and all the variables

2y-6

Back to the equation:

-(2y-6)



We get rid of parentheses

-2y+6-2=0

We add all the numbers together, and all the variables

-2y+4=0

We move all terms containing y to the left, all other terms to the right

-2y=-4

y=-4/-2

y=+2

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