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-2=3x^2+7x-6
We move all terms to the left:
-2-(3x^2+7x-6)=0
We get rid of parentheses
-3x^2-7x+6-2=0
We add all the numbers together, and all the variables
-3x^2-7x+4=0
a = -3; b = -7; c = +4;
Δ = b2-4ac
Δ = -72-4·(-3)·4
Δ = 97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{97}}{2*-3}=\frac{7-\sqrt{97}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{97}}{2*-3}=\frac{7+\sqrt{97}}{-6} $
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