-2T+12+32/T

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Solution for -2T+12+32/T equation: 


D( T )

T = 0

T = 0

T = 0

T in (-oo:0) U (0:+oo)

32/T-2*T+12 = 0

32*T^-1-2*T^1+12*T^0 = 0

(12*T^1-2*T^2+32*T^0)/(T^1) = 0 // * T^2

T^1*(12*T^1-2*T^2+32*T^0) = 0

T^1

12*T-2*T^2+32 = 0

12*T-2*T^2+32 = 0

DELTA = 12^2-(-2*4*32)

DELTA = 400

DELTA > 0

T = (400^(1/2)-12)/(-2*2) or T = (-400^(1/2)-12)/(-2*2)

T = -2 or T = 8

T in { -2, 8} 

T in { -2, 8 }

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