-2a(3a-2)=1/3(7-3a)

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Solution for -2a(3a-2)=1/3(7-3a) equation: 



-2a(3a-2)=1/3(7-3a)

We move all terms to the left:

-2a(3a-2)-(1/3(7-3a))=0



Domain of the equation: 3(7-3a))!=0

a∈R



We add all the numbers together, and all the variables

-2a(3a-2)-(1/3(-3a+7))=0

We multiply parentheses

-6a^2+4a-(1/3(-3a+7))=0

We multiply all the terms by the denominator


-6a^2*3(-3a+7))+4a*3(-3a+7))-(1=0

We add all the numbers together, and all the variables

-6a^2*3(-3a+7))+4a*3(-3a=0

Wy multiply elements

-54a^4(--3a=0

We do not support eapression: a^4(

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