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-2a+3/a+1=0
Domain of the equation: a!=0We multiply all the terms by the denominator
a∈R
-2a*a+1*a+3=0
We add all the numbers together, and all the variables
a-2a*a+3=0
Wy multiply elements
-2a^2+a+3=0
a = -2; b = 1; c = +3;
Δ = b2-4ac
Δ = 12-4·(-2)·3
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-5}{2*-2}=\frac{-6}{-4} =1+1/2 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+5}{2*-2}=\frac{4}{-4} =-1 $
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