-2b(-3b)=-b

Solution for -2b(-3b)=-b equation:

-2b(-3b)=-b

We move all terms to the left:

-2b(-3b)-(-b)=0

We add all the numbers together, and all the variables

-2b(-3b)-(-1b)=0

We multiply parentheses

6b^2-(-1b)=0

We get rid of parentheses

6b^2+1b=0

We add all the numbers together, and all the variables

6b^2+b=0

a = 6; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·6·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*6}=\frac{-2}{12}
=-1/6
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*6}=\frac{0}{12}
=0
$