-2b+12(b-4)=8(-12b-6)

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Solution for -2b+12(b-4)=8(-12b-6) equation: 



-2b+12(b-4)=8(-12b-6)

We move all terms to the left:

-2b+12(b-4)-(8(-12b-6))=0

We multiply parentheses

-2b+12b-(8(-12b-6))-48=0



We calculate terms in parentheses: -(8(-12b-6)), so:

8(-12b-6)

We multiply parentheses

-96b-48

Back to the equation:

-(-96b-48)



We add all the numbers together, and all the variables

10b-(-96b-48)-48=0

We get rid of parentheses

10b+96b+48-48=0

We add all the numbers together, and all the variables

106b=0

b=0/106

b=0

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