-2b+2(b+5)=7+3(11+5b)

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Solution for -2b+2(b+5)=7+3(11+5b) equation: 



-2b+2(b+5)=7+3(11+5b)

We move all terms to the left:

-2b+2(b+5)-(7+3(11+5b))=0

We add all the numbers together, and all the variables

-2b+2(b+5)-(7+3(5b+11))=0

We multiply parentheses

-2b+2b-(7+3(5b+11))+10=0



We calculate terms in parentheses: -(7+3(5b+11)), so:

7+3(5b+11)

determiningTheFunctionDomain
3(5b+11)+7

We multiply parentheses

15b+33+7

We add all the numbers together, and all the variables

15b+40

Back to the equation:

-(15b+40)



We add all the numbers together, and all the variables

-(15b+40)+10=0

We get rid of parentheses

-15b-40+10=0

We add all the numbers together, and all the variables

-15b-30=0

We move all terms containing b to the left, all other terms to the right

-15b=30

b=30/-15

b=-2

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