-2c(-c-12)=2c-12

Solution for -2c(-c-12)=2c-12 equation:

-2c(-c-12)=2c-12

We move all terms to the left:

-2c(-c-12)-(2c-12)=0

We add all the numbers together, and all the variables

-2c(-1c-12)-(2c-12)=0

We multiply parentheses

2c^2+24c-(2c-12)=0

We get rid of parentheses

2c^2+24c-2c+12=0

We add all the numbers together, and all the variables

2c^2+22c+12=0

a = 2; b = 22; c = +12;
Δ = b2-4ac
Δ = 222-4·2·12
Δ = 388
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{388}=\sqrt{4*97}=\sqrt{4}*\sqrt{97}=2\sqrt{97}$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-2\sqrt{97}}{2*2}=\frac{-22-2\sqrt{97}}{4}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+2\sqrt{97}}{2*2}=\frac{-22+2\sqrt{97}}{4}
$