-2c+4(3c+8)=-5c-2(6-3c)

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Solution for -2c+4(3c+8)=-5c-2(6-3c) equation: 



-2c+4(3c+8)=-5c-2(6-3c)

We move all terms to the left:

-2c+4(3c+8)-(-5c-2(6-3c))=0

We add all the numbers together, and all the variables

-2c+4(3c+8)-(-5c-2(-3c+6))=0

We multiply parentheses

-2c+12c-(-5c-2(-3c+6))+32=0



We calculate terms in parentheses: -(-5c-2(-3c+6)), so:

-5c-2(-3c+6)

We multiply parentheses

-5c+6c-12

We add all the numbers together, and all the variables

c-12

Back to the equation:

-(c-12)



We add all the numbers together, and all the variables

10c-(c-12)+32=0

We get rid of parentheses

10c-c+12+32=0

We add all the numbers together, and all the variables

9c+44=0

We move all terms containing c to the left, all other terms to the right

9c=-44

c=-44/9

c=-4+8/9

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