-2c-(3c-5)+c=11

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Solution for -2c-(3c-5)+c=11 equation: 



-2c-(3c-5)+c=11

We move all terms to the left:

-2c-(3c-5)+c-(11)=0

We add all the numbers together, and all the variables

-1c-(3c-5)-11=0

We get rid of parentheses

-1c-3c+5-11=0

We add all the numbers together, and all the variables

-4c-6=0

We move all terms containing c to the left, all other terms to the right

-4c=6

c=6/-4

c=-1+1/2

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