-2c-9c-2=-3c2

Solution for -2c-9c-2=-3c2 equation:

-2c-9c-2=-3c^2

We move all terms to the left:

-2c-9c-2-(-3c^2)=0

We add all the numbers together, and all the variables

-(-3c^2)-11c-2=0

We get rid of parentheses

3c^2-11c-2=0

a = 3; b = -11; c = -2;
Δ = b2-4ac
Δ = -112-4·3·(-2)
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{145}}{2*3}=\frac{11-\sqrt{145}}{6}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{145}}{2*3}=\frac{11+\sqrt{145}}{6}
$