-2f(2)+3=f(n+1)

Solution for -2f(2)+3=f(n+1) equation:

Simplifying
-2f(2) + 3 = f(n + 1)

Reorder the terms for easier multiplication:
-2 * 2f + 3 = f(n + 1)

Multiply -2 * 2
-4f + 3 = f(n + 1)

Reorder the terms:
3 + -4f = f(n + 1)

Reorder the terms:
3 + -4f = f(1 + n)
3 + -4f = (1 * f + n * f)
3 + -4f = (1f + fn)

Solving
3 + -4f = 1f + fn

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Add '-1f' to each side of the equation.
3 + -4f + -1f = 1f + -1f + fn

Combine like terms: -4f + -1f = -5f
3 + -5f = 1f + -1f + fn

Combine like terms: 1f + -1f = 0
3 + -5f = 0 + fn
3 + -5f = fn

Add '-1fn' to each side of the equation.
3 + -5f + -1fn = fn + -1fn

Combine like terms: fn + -1fn = 0
3 + -5f + -1fn = 0

Add '-3' to each side of the equation.
3 + -5f + -3 + -1fn = 0 + -3

Reorder the terms:
3 + -3 + -5f + -1fn = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -5f + -1fn = 0 + -3
-5f + -1fn = 0 + -3

Combine like terms: 0 + -3 = -3
-5f + -1fn = -3

Reorder the terms:
3 + -5f + -1fn = -3 + 3

Combine like terms: -3 + 3 = 0
3 + -5f + -1fn = 0

The solution to this equation could not be determined.