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-2h^2+11h+21=0
a = -2; b = 11; c = +21;
Δ = b2-4ac
Δ = 112-4·(-2)·21
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-17}{2*-2}=\frac{-28}{-4} =+7 $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+17}{2*-2}=\frac{6}{-4} =-1+1/2 $
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