-2k+5+5k-8=2(k+2)-(k+3)

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Solution for -2k+5+5k-8=2(k+2)-(k+3) equation: 



-2k+5+5k-8=2(k+2)-(k+3)

We move all terms to the left:

-2k+5+5k-8-(2(k+2)-(k+3))=0

We add all the numbers together, and all the variables

3k-(2(k+2)-(k+3))-3=0



We calculate terms in parentheses: -(2(k+2)-(k+3)), so:

2(k+2)-(k+3)

We multiply parentheses

2k-(k+3)+4

We get rid of parentheses

2k-k-3+4

We add all the numbers together, and all the variables

k+1

Back to the equation:

-(k+1)



We get rid of parentheses

3k-k-1-3=0

We add all the numbers together, and all the variables

2k-4=0

We move all terms containing k to the left, all other terms to the right

2k=4

k=4/2

k=2

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