-2k+k=-4(k-2)-(2-2k)

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Solution for -2k+k=-4(k-2)-(2-2k) equation: 



-2k+k=-4(k-2)-(2-2k)

We move all terms to the left:

-2k+k-(-4(k-2)-(2-2k))=0

We add all the numbers together, and all the variables

-2k+k-(-4(k-2)-(-2k+2))=0

We add all the numbers together, and all the variables

-1k-(-4(k-2)-(-2k+2))=0



We calculate terms in parentheses: -(-4(k-2)-(-2k+2)), so:

-4(k-2)-(-2k+2)

We multiply parentheses

-4k-(-2k+2)+8

We get rid of parentheses

-4k+2k-2+8

We add all the numbers together, and all the variables

-2k+6

Back to the equation:

-(-2k+6)



We get rid of parentheses

-1k+2k-6=0

We add all the numbers together, and all the variables

k-6=0

We move all terms containing k to the left, all other terms to the right

k=6

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