-2k-5=2-4k-(k-1)

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Solution for -2k-5=2-4k-(k-1) equation: 



-2k-5=2-4k-(k-1)

We move all terms to the left:

-2k-5-(2-4k-(k-1))=0



We calculate terms in parentheses: -(2-4k-(k-1)), so:

2-4k-(k-1)

determiningTheFunctionDomain
-4k-(k-1)+2

We get rid of parentheses

-4k-k+1+2

We add all the numbers together, and all the variables

-5k+3

Back to the equation:

-(-5k+3)



We get rid of parentheses

-2k+5k-3-5=0

We add all the numbers together, and all the variables

3k-8=0

We move all terms containing k to the left, all other terms to the right

3k=8

k=8/3

k=2+2/3

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