-2n+2(n-2)=-(1-2n)-3n

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Solution for -2n+2(n-2)=-(1-2n)-3n equation:



-2n+2(n-2)=-(1-2n)-3n
We move all terms to the left:
-2n+2(n-2)-(-(1-2n)-3n)=0
We add all the numbers together, and all the variables
-2n+2(n-2)-(-(-2n+1)-3n)=0
We multiply parentheses
-2n+2n-(-(-2n+1)-3n)-4=0
We calculate terms in parentheses: -(-(-2n+1)-3n), so:
-(-2n+1)-3n
We add all the numbers together, and all the variables
-3n-(-2n+1)
We get rid of parentheses
-3n+2n-1
We add all the numbers together, and all the variables
-1n-1
Back to the equation:
-(-1n-1)
We add all the numbers together, and all the variables
-(-1n-1)-4=0
We get rid of parentheses
1n+1-4=0
We add all the numbers together, and all the variables
n-3=0
We move all terms containing n to the left, all other terms to the right
n=3

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