-2n-7(1+4n)=5-6(n+2)

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Solution for -2n-7(1+4n)=5-6(n+2) equation: 



-2n-7(1+4n)=5-6(n+2)

We move all terms to the left:

-2n-7(1+4n)-(5-6(n+2))=0

We add all the numbers together, and all the variables

-2n-7(4n+1)-(5-6(n+2))=0

We multiply parentheses

-2n-28n-(5-6(n+2))-7=0



We calculate terms in parentheses: -(5-6(n+2)), so:

5-6(n+2)

determiningTheFunctionDomain
-6(n+2)+5

We multiply parentheses

-6n-12+5

We add all the numbers together, and all the variables

-6n-7

Back to the equation:

-(-6n-7)



We add all the numbers together, and all the variables

-30n-(-6n-7)-7=0

We get rid of parentheses

-30n+6n+7-7=0

We add all the numbers together, and all the variables

-24n=0

n=0/-24

n=0

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