-2p(2p-4)=3(p+12)

Solution for -2p(2p-4)=3(p+12) equation:

-2p(2p-4)=3(p+12)

We move all terms to the left:

-2p(2p-4)-(3(p+12))=0

We multiply parentheses

-4p^2+8p-(3(p+12))=0


We calculate terms in parentheses: -(3(p+12)), so:

3(p+12)

We multiply parentheses

3p+36

Back to the equation:

-(3p+36)


We get rid of parentheses

-4p^2+8p-3p-36=0

We add all the numbers together, and all the variables

-4p^2+5p-36=0

a = -4; b = 5; c = -36;
Δ = b2-4ac
Δ = 52-4·(-4)·(-36)
Δ = -551
Delta is less than zero, so there is no solution for the equation