-2p(p-5)+7p=5

Solution for -2p(p-5)+7p=5 equation:

-2p(p-5)+7p=5

We move all terms to the left:

-2p(p-5)+7p-(5)=0

We add all the numbers together, and all the variables

7p-2p(p-5)-5=0

We multiply parentheses

-2p^2+7p+10p-5=0

We add all the numbers together, and all the variables

-2p^2+17p-5=0

a = -2; b = 17; c = -5;
Δ = b2-4ac
Δ = 172-4·(-2)·(-5)
Δ = 249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{249}}{2*-2}=\frac{-17-\sqrt{249}}{-4}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{249}}{2*-2}=\frac{-17+\sqrt{249}}{-4}
$