-2p-5(2+2p)=6(p-4)-2

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Solution for -2p-5(2+2p)=6(p-4)-2 equation: 



-2p-5(2+2p)=6(p-4)-2

We move all terms to the left:

-2p-5(2+2p)-(6(p-4)-2)=0

We add all the numbers together, and all the variables

-2p-5(2p+2)-(6(p-4)-2)=0

We multiply parentheses

-2p-10p-(6(p-4)-2)-10=0



We calculate terms in parentheses: -(6(p-4)-2), so:

6(p-4)-2

We multiply parentheses

6p-24-2

We add all the numbers together, and all the variables

6p-26

Back to the equation:

-(6p-26)



We add all the numbers together, and all the variables

-12p-(6p-26)-10=0

We get rid of parentheses

-12p-6p+26-10=0

We add all the numbers together, and all the variables

-18p+16=0

We move all terms containing p to the left, all other terms to the right

-18p=-16

p=-16/-18

p=8/9

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