-2r+3(2r-4)=10r+12

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Solution for -2r+3(2r-4)=10r+12 equation: 



-2r+3(2r-4)=10r+12

We move all terms to the left:

-2r+3(2r-4)-(10r+12)=0

We multiply parentheses

-2r+6r-(10r+12)-12=0

We get rid of parentheses

-2r+6r-10r-12-12=0

We add all the numbers together, and all the variables

-6r-24=0

We move all terms containing r to the left, all other terms to the right

-6r=24

r=24/-6

r=-4

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