-2r+32=6-5(2r+3)

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Solution for -2r+32=6-5(2r+3) equation: 



-2r+32=6-5(2r+3)

We move all terms to the left:

-2r+32-(6-5(2r+3))=0



We calculate terms in parentheses: -(6-5(2r+3)), so:

6-5(2r+3)

determiningTheFunctionDomain
-5(2r+3)+6

We multiply parentheses

-10r-15+6

We add all the numbers together, and all the variables

-10r-9

Back to the equation:

-(-10r-9)



We get rid of parentheses

-2r+10r+9+32=0

We add all the numbers together, and all the variables

8r+41=0

We move all terms containing r to the left, all other terms to the right

8r=-41

r=-41/8

r=-5+1/8

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