-2r+6(r-1)+3r-(4-r)=(r+5)-5

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Solution for -2r+6(r-1)+3r-(4-r)=(r+5)-5 equation:


-2r+6(r-1)+3r-(4-r)=(r+5)-5

We simplify the equation to the form, which is simple to understand
-2r+6(r-1)+3r-(4-r)=(r+5)-5

Reorder the terms in parentheses
-2r+(+6r-6)+3r-(4-r)=(r+5)-5

Remove unnecessary parentheses
-2r+6r-6+3r-(+4-r+)=+(+r+5+)-5

Remove unnecessary parentheses
-2r+6r-6+3r-4+1r=(r+5)-5

Remove unnecessary parentheses
-2r+6r-6+3r-4+1r=r+5-5

We move all terms containing r to the left and all other terms to the right.
-2r+6r+3r+1r-1r=+5-5+6+4

We simplify left and right side of the equation.
+7r=+10

We divide both sides of the equation by 7 to get r.
r=1.4285714285714

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