-2r-10(r+12)=-3(4r-2)-2

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Solution for -2r-10(r+12)=-3(4r-2)-2 equation:


Simplifying
-2r + -10(r + 12) = -3(4r + -2) + -2

Reorder the terms:
-2r + -10(12 + r) = -3(4r + -2) + -2
-2r + (12 * -10 + r * -10) = -3(4r + -2) + -2
-2r + (-120 + -10r) = -3(4r + -2) + -2

Reorder the terms:
-120 + -2r + -10r = -3(4r + -2) + -2

Combine like terms: -2r + -10r = -12r
-120 + -12r = -3(4r + -2) + -2

Reorder the terms:
-120 + -12r = -3(-2 + 4r) + -2
-120 + -12r = (-2 * -3 + 4r * -3) + -2
-120 + -12r = (6 + -12r) + -2

Reorder the terms:
-120 + -12r = 6 + -2 + -12r

Combine like terms: 6 + -2 = 4
-120 + -12r = 4 + -12r

Add '12r' to each side of the equation.
-120 + -12r + 12r = 4 + -12r + 12r

Combine like terms: -12r + 12r = 0
-120 + 0 = 4 + -12r + 12r
-120 = 4 + -12r + 12r

Combine like terms: -12r + 12r = 0
-120 = 4 + 0
-120 = 4

Solving
-120 = 4

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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